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Catherine rolls a -sided die five times, and the product of her rolls is 300. How many different sequences of rolls could there have been? (The order of the rolls matters.)

 

Hi.  Some people have posted questions similar to this one but their not that same.  I've looked at those ones and tried to apply it to this one, but it was always wrong.  Pls halp.

 Apr 15, 2022
 #1
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a what sided die

 Apr 15, 2022
 #2
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6 sided.

Guest Apr 15, 2022
 #3
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The prime factorization of 300 is 2 × 2 × 3 × 5 × 5, so you try to find the number of combinations of 2 x 2 x 3 x 5 x 5 

 Apr 15, 2022
edited by qjin27  Apr 15, 2022
edited by qjin27  Apr 15, 2022
 #4
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I have gotten that answer before.  It is incorrect.  Can you show how you got it?

Guest Apr 15, 2022
 #5
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I'm trying to figure out a smarter way to calcaulte the combinitions that don't involve casework, cause i'm too lazy to do it

qjin27  Apr 15, 2022
 #6
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300 factors as     5^2 * 2^2 * 3

 

I see the possible identifiable sequences as

5 * 5 * 2 * 2 * 3 =    5!/(2! * 2!)  = 30

5 * 5 * 4 * 3 * 1 =    5! / 2! =  60

5 * 5  * 6 * 2 * 1 =  5! / 2! =  60

 

I get  150

 

Anyone else ???

 

 

cool cool cool    

 Apr 15, 2022
 #7
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I just got that before I saw your post.  That is correct!!  Can you please try and answer this question? https://web2.0calc.com/questions/pls-halp_27

Guest Apr 15, 2022
 #8
avatar+124598 
+1

Although  I don't know the answer to this.....here is a  very similar question answered by amy :

 

https://web2.0calc.com/questions/help-is-appreciated-thank-you

 

I think that you only need to change a few numbers and  then  graph the inequalities.....it should give  you a trianglular area that you can  calculate  to the total area

 

 

cool cool cool

CPhill  Apr 15, 2022

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