Here is an update on the probability puzzles!
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Easier one (hasn't been answered yet):
The fabulous game host Steve offer you a bag with 5001 pearls of which 2501 are white and 2500 are black. He asks you to draw as many pearls from the bag as you desire without looking. Steve then tells you how many black and white pearls you drew. If there are equally as much white as black pearls in the draw you gain €10 for each pearl you drew. How many pearls should you draw?
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Hard one:
All right, so here's a classic one.
Jason and Tyrell are in a classroom of 23 students.
At some point Tyrell finds out that some of his classmates have the same birthday.
In surprise he exclaims; 'what a surprise!'.
Jason however, says it is more likely for two or more people to have the same birthday in their class than it is for noone to have the same birthday.
Assume any birthday is equally likely to another and pretend leap years don't exist. (it makes it a lot easier)
What are the odds of two or more people sharing their birthday?
Tip: You might find that the web2.0calc.com calculator has trouble calculating this. If you prefer not to do it by hand I suggest using www.wolframalpha.com
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