Shadowbolt04

$${\frac{{\mathtt{3}}}{{\mathtt{4}}}}{\mathtt{\,\times\,}}{\mathtt{p}}{\mathtt{\,-\,}}{\mathtt{2}} = {\frac{{\mathtt{3}}}{{\mathtt{8}}}} \Rightarrow {\mathtt{p}} = {\frac{{\mathtt{19}}}{{\mathtt{6}}}} \Rightarrow {\mathtt{p}} = {\mathtt{3.166\: \!666\: \!666\: \!666\: \!666\: \!7}}$$

4 6/7 is the answer.

Multiply the exponent of x by 2giving

The answer is

x^2 evaluates to 

Multiply x and 9

Multiply x and 1

The x just gets copied along.

The answer is x

x

9*x evaluates to 9x

x^2-9*x evaluates to 

The answer is

x^2-9*x+14 evaluates to 

To divide by x

divide each term in by x term by term.

To divide by x

Divide by x by subtracting the exponents, and keeping the x, to get x

The answer is x

 ÷ x = x

To divide x by x

Divide x by x by subtracting the exponents, and keeping the x, to get 1

Why 1? since subtracting the exponents gives zero, the x completely drops out.This because anything (other than 0) to the 0th power is 1.

-9x ÷ x = -9

To divide 1 by x

The x just gets copied along in the denominator.

The answer is

14 ÷ x =

(x^2-9*x+14)/x evaluates to 

-9 - 7 = -16

The answer is

(x^2-9*x+14)/x-7 evaluates to 

Multiply the exponent of n by 2giving

The answer is

n^2 evaluates to 

Multiply n and 3

Multiply n and 1

The n just gets copied along.

The answer is n

n

3*n evaluates to 3n

To divide n by 1

The n just gets copied along in the numerator.

The answer is n

3*n/3 evaluates to n

Multiply and n

Multiply the and n

Multiply and n

Combine the and n by adding the exponents, and keeping the n, to get

The answer is

3*n/3*n^2 evaluates to 

There are 12 total counters. You get 12 by doing 5+6+1. Take the amount of red counters and subtract it from the total number of counters by doing 12-5. Your answer is 7. Put that over the total, and the probability of Jim not picking a red counter is 7/12.

Hope this helps 

$${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}} \Rightarrow {\mathtt{x}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{4}}}} \Rightarrow {\mathtt{x}} = -{\mathtt{0.25}}$$

$${\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{z}} = {\mathtt{21}} \Rightarrow {\mathtt{x}} = {\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{z}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{21}}\right)}{{\mathtt{4}}}}$$

$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{z}} = -{\mathtt{15}} \Rightarrow {\mathtt{x}} = {\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{z}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{15}}\right)}{{\mathtt{3}}}}$$

$${\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{z}} = {\mathtt{15}} \Rightarrow {\mathtt{x}} = {\frac{\left({\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{z}}{\mathtt{\,-\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{15}}\right)}{{\mathtt{7}}}}$$

$${\frac{\left({\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}\right)}{{\mathtt{3}}}} = {\mathtt{7}} \Rightarrow {\mathtt{x}} = {\mathtt{3}}$$

X is the missing number.

Go to this link.

http://web2.0calc.com/questions/how-do-i-type-in-fractions

$${\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}} = {\mathtt{6}} \Rightarrow {\mathtt{x}} = {\mathtt{\,-\,}}{\frac{{\mathtt{5}}}{{\mathtt{2}}}} \Rightarrow {\mathtt{x}} = -{\mathtt{2.5}}$$