$${\frac{{\mathtt{3}}{n}}{{\mathtt{3}}\left[{{n}}^{{\mathtt{2}}}\right]}}$$ Please solve and explain how.
You can cancel out the 3n on the numerator and the denominator, leaving you with $${\frac{{\mathtt{1}}}{{\mathtt{n}}}}$$
Multiply the exponent of n by 2giving
The answer is
n^2 evaluates to
Multiply n and 3
Multiply n and 1
The n just gets copied along.
The answer is n
n
3*n evaluates to 3n
To divide n by 1
The n just gets copied along in the numerator.
The answer is n
3*n/3 evaluates to n
Multiply and n
Multiply the and n
Multiply and n
Combine the and n by adding the exponents, and keeping the n, to get
The answer is
3*n/3*n^2 evaluates to
Sadly, you were wrong. I banish thee forever for using an online calculator. I will never trust you or your answers ever again.
You can cancel out the 3n on the numerator and the denominator, leaving you with $${\frac{{\mathtt{1}}}{{\mathtt{n}}}}$$