SparklingWater2

if the two points can be the same point, then the answer is $\boxed{\frac{(4+4)\cdot20}{20\cdot20}=\frac25}$

if the two points are different, then the answer is $\boxed{\frac{(4+3)\cdot20}{20\cdot19}=\frac7{19}}$

Honestly, I rly like graphing problems :P

if it's a reflection, then the line that contains the reflected point and the real point is perpendicular to y=2x+5, so the equation would be y=-1/2x+b, and we can plug in (6,2) for x and y, and we get b=1. now, we can find the intersection, then multiply how much the x coordinate moved and how much the y coordinate moved by 2 and add those to the original point, and voila, we get our answer.

intersection: 0=5/2x+4

5/2x=-4

x=-8/5

y=4/5+5/5=9/5

so the intersection is (-8/5,9/5). 

the x coordinate moved by -38/5, while the y coordinate moved by 1/5, so we need to move the x coordinate by -76/5, and the y coordinate by 2/5, so the coordinate of B=$\boxed{(-\frac{46}{5},\frac{12}{5})}$

It's an accute triangle so if we extend CH, the base is orthogonal/perpendicular to AB, so we can find ACH easily: 180-(90+43)=$\boxed{47^\circ}$

$\frac{(45+116)(116-45+1)}{2}=\boxed{5796}$

3sqrt3/2=BD*CE/2=(3^2+sqrt3^2)*CE/2=2sqrt3*3/2/2

CE=$\boxed{\frac32}$

6!/3!*2!=720/12=$\boxed{60}$

V=73400=68000+1200(n-3)

5400=1200(n-3)=1200(9/2)

so n=3+9/2=$\boxed{15/2 \  years}$ 

a

6!=$\boxed{720}$

b

6!/12=$\boxed{60}$

c

6!-60=$\boxed{660}$

lets call FD x.

18^2+x^2=(24-x)^2

324+x^2=576+x^2-48x

48x=252

x=$\boxed{\frac{21}{4}}$

A rhombus has two pairs of angles, and all 4 added together is 360, or one of each pair together is 180. This means that the other angle of the rhombus is 30. we also know that the area of the rhombus is diagonal1*diagonal2/2, or if we slant it so that one of the edges is like a base, we can do the height*base without dividing by 2. We'll use the second option, because if we draw a line from a corner orthogonal/perpendicular to the base, we have a 30,60,90 triangle. we know that the hypotenuse or the edge of the rhombus is 2 times the height of the triangle, so we can say that x^2/2=50, where x is the length of the edge, so simplifying, we get x=10, so the perimeter of the rhombus is 4x=$\boxed{40}$