+0  
 
0
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avatar+496 

the inverse of function $f(x) = \dfrac{2x-1}{x+5}$ is written in the form of $f^{-1}(x)=\dfrac{ax+b}{cx+d}$, where a, b, c, and d are all real numbers. If you could, try to find $\dfrac{a}{c}.$

 Apr 15, 2021
edited by SparklingWater2  Apr 15, 2021
 #1
avatar+180 
+1

There is already an answer/

 

https://web2.0calc.com/questions/help-asapp_1

 

Check this link and let me know if it's wrong.

 

Hope this helps! laugh

 Apr 15, 2021
 #2
avatar+496 
0

It's wrong :P

 Apr 15, 2021
 #3
avatar+180 
0

Ok, thank you for telling me. I will solve it immediately.

Mathdory  Apr 15, 2021
 #4
avatar+32113 
+3

Replace x by y and f(x) by x in the function definition, then rearrange to  find y:

 

\(x = \frac{2y-1}{y+5}\)   so  \(x(y+5)=2y-1\)  

 

Collect the y's   \(y(x-2)+5x = -1\)  or \(y = \frac{-5x-1}{x-2}\)

 

which means \(f^{-1}(x)=\frac{-5x-1}{x-2}\)

 

So a /c= -5/1

 Apr 15, 2021
edited by Alan  Apr 15, 2021

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