In rectangle $ABCD$, shown here, $\overline{CE}$ is perpendicular to $\overline{BD}$. If $BC = \sqrt 3$ and $DC = 3$, what is $CE$?
3sqrt3/2=BD*CE/2=(3^2+sqrt3^2)*CE/2=2sqrt3*3/2/2
CE=$\boxed{\frac32}$
+195 
+592 
