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In rectangle $ABCD$, shown here, $\overline{CE}$ is perpendicular to $\overline{BD}$. If $BC = \sqrt 3$ and $DC = 3$, what is $CE$?

 Feb 28, 2021
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3sqrt3/2=BD*CE/2=(3^2+sqrt3^2)*CE/2=2sqrt3*3/2/2

CE=$\boxed{\frac32}$

 Feb 28, 2021

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