SportzGuy2310

Yes, Melody is correct. You are given irrelevant, unneeded information. The answer to this is 17/38

The ending point of the path Franklin made depends on all the moves Franklin made, not the order. Consider a random 10-step path Franklin could take. NESWNNESEW (N for North, S for south, W for west, E for East.  Reduce our path by cancelling each E-W and each N-S pair, which will not change our endpoint. So our example reduces to NE. Notice that our reduced path must have an even number of moves, and it is thus possible to end at any point (x,y) where x+y is even and |x| + |y| is no greater than 10.'

If |x| + |y| = 0, there is one possibility for (x,y).

If |x| + |y|  <= (less than equal to) 2, there are 9 possible paths ((0,0) (-+1,-+1) (0, +-2) (+-2,0)); these solutions will form a 3x3 diagonal grid

The solutions with |x| + |y| <= 10 will form an 11x11 grid, so there are 11^2= 121 ways

The ending point of the path Franklin made depends on all the moves Franklin made, not the order. Consider a random 10-step path Franklin could take. NESWNNESEW (N for North, S for south, W for west, E for East.  Reduce our path by cancelling each E-W and each N-S pair, which will not change our endpoint. So our example reduces to NE. Notice that our reduced path must have an even number of moves, and it is thus possible to end at any point (x,y) where x+y is even and |x| + |y| is no greater than 10.'

If |x| + |y| = 0, there is one possibility for (x,y).

If |x| + |y|  <= (less than equal to) 2, there are 9 possible paths ((0,0) (-+1,-+1) (0, +-2) (+-2,0)); these solutions will form a 3x3 diagonal grid

The solutions with |x| + |y| <= 10 will form an 11x11 grid, so there are 11^2= 121 ways

There is nothing to solve for, so \(IDK\)

3030 stamps

Solve 3a + 4b = 5a - 6b + 24 - 3a for a in terms of b.  

                                                            3a + 4b  =  5a – 6b + 24 – 3a   

You just add up the like terms.  

                                                            3a + 4b  =  2a – 6b + 24  

And subtract 2a from both sides  

                                                              a + 4b  =  – 6b + 24  

And subtract 4b from both sides  

                                                                      a  =  – 10b + 24  

When you get better at it, you  

can combine simple steps like  

addition/subtraction of terms.  

It's conventional to place the  

positive number ahead of the  

negative number.  

                                                                       a  =  24 – 10b  

If I give my brother 5 dollars, then we will have the same amount of money. If instead he gives me 25 dollars, then I'll have twice as much money as he will have. How much money does my brother currently have (in dollars)?   

Let M stand for My original amount  

Let B stand for Brother's original amount   

                                                             (M – 5)  =  (B + 5)   

                                                             (M + 25)  =  (2)(B – 25)  

                                                              M – 5  =  B + 5   gives us  M = B + 10    (1)  

                                                              M + 25  =  2B – 50                                 (2)  

Substitute the value of M from (1)   

into the equation (2)                             B + 10 + 25  =  2B – 50   

Combine like terms                                          85  =  B    

Brother has 85 dollars before they start giving each other money.   

The problem doesn't ask for My original amount but it's B + 10 = 95  

Check answer  

If I give my brother 5, then I'll have 90 and so will he, so we have the same.  

If my brother gives me 25, then I'll have 120 and my brother will have 60. 

A diagram/image would be useful while solving this problem :D

Guest's answer is correct. The bubble gum costs 25 cents.