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13

1

+9

There is a point $P$ inside equilateral $\triangle ABC$ such that $PA=PB=PC=x.$ We know $[ABC]=\dfrac{\sqrt 3}{3}.$ Find $x.$

There is a point $P$ inside equilateral $\triangle ABC$ such that $PA=PB=PC=x.$ We know $[ABC]=\dfrac{\sqrt 3}{3}.$ Find $x.$

sticknotes.com Jul 20, 2024

+1

34

1

+9

Find tan 7pi/4

I know how to get the answer, but are we expected to know and memorize the different values of cosine and sin with radians. Like are we supposed to know what sin 7pi/4 without a calculator. Because the last step is (sin 7pi/4)/(cos 7pi/4). I have absolutely read more ..

sticknotes.com Apr 10, 2024