TheLovely1

I need to know the equation... (to solve it)

Can you correct it if I'm wrong?

\(10^{(\sqrt(7*(5^{33})^{2})))}\)

\(\sqrt(10*2) \\ \\\sqrt(20) \\ \\\sqrt(4*5) \\ \\2\sqrt(5)\)

Solution:

\(2\sqrt(5)\)

Not entirely sure what you mean by all the work, but I'll do my best.

0.1=\(\frac{1}{10}\)

Checking work:

  __________

1)10                  = 0.1

If you need an explanation and I'm not clear, reply to my answer.

SOH CAH TOA.

\(sin=\frac{opposite}{hypotenuse} \\ \\sin=\frac{12}{37}\)

So, if I'm correct, (-1,0) would be the minimum point, and (0,pi/6) would be the midline point?

Thank you!~

Nice answer!~

Hello, ElitBabbi!~

Hope your day was fine!~

Back to the maths.

1a) Graphing is useful in many ways. Graphing was invented by Rene Descartes, where we get the name, "Cartesian Plane" from.

Graphs are a common method to visually illustrate relationships in the data. The purpose of a graph is to present data that are too numerous or complicated to be described adequately in the text and in less space. 

Thus, the graph has many useful purposes. For some neatly built cities, with perfect square-blocks, you could, theoretically, plot your home and places of interest, and figure out how many blocks you would have to travel, based on the number of blocks on the map you have to cover-unless you can fly. Then... Yeah... I don't know.

You can use all sorts of graphs, as well. You can use a line graph to measure how much money is going toward things you don't need each month and work to get a negative slope on the graph-thereby saving money. There are loads of practical applications for graphs, and I can't think of anything incredibly useful right now, unfortunately.

1b) https://www.desmos.com/calculator/41eqoeuaub You can do the rest!

-TheLovely1

Hello, Guest!~

I'm going to elaborate on Electric Pavlov's excellent answer.

So, basically, the Law of Sines says that, according to Khanacademy, a side labeled, "A" over the sine * opposite of it, which is, angle "a", is equal to a side labeled, "B", over the sine * opposite of that side, which is the angle "b".

In short, you end up with, \(\frac{Side\ A}{Angle\ a}=\frac{Side\ B}{Angle\ b}\), and you can add the third side the same way: \(\frac{Side\ A}{Angle\ a}=\frac{Side\ B}{Angle\ b}=​​\frac{Side\ C}{Angle\ c}\)

For your case, we get:

 \(\frac{sin(70)}{5.7}=\frac{x}{5} \\ \\ sin(x)*5.7=sin(70)*5 \\ \\sin(x)=\frac{5sin(70)}{5.7} \\ \\x=sin^{-1}(\frac{5sin(70)}{5.7})\)

I do hope the math is correct.

From here, you can just plug it in!

I hope you did take away something from my answer!

-TheLovely1