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Find x in this please

 

 Jul 26, 2020
 #1
avatar+26852 
+2

Law of sines

 

sin 70o  / 5.7 = sin xo / 5       solve for 'x'

 Jul 26, 2020
 #3
avatar+75 
+1

Nice answer!~

TheLovely1  Jul 26, 2020
 #2
avatar+75 
+1

Hello, Guest!~

 

I'm going to elaborate on Electric Pavlov's excellent answer.

 

So, basically, the Law of Sines says that, according to Khanacademy, a side labeled, "A" over the sine * opposite of it, which is, angle "a", is equal to a side labeled, "B", over the sine * opposite of that side, which is the angle "b".

 

In short, you end up with, \(\frac{Side\ A}{Angle\ a}=\frac{Side\ B}{Angle\ b}\), and you can add the third side the same way: \(\frac{Side\ A}{Angle\ a}=\frac{Side\ B}{Angle\ b}=​​\frac{Side\ C}{Angle\ c}\)

 

For your case, we get:

 \(\frac{sin(70)}{5.7}=\frac{x}{5} \\ \\ sin(x)*5.7=sin(70)*5 \\ \\sin(x)=\frac{5sin(70)}{5.7} \\ \\x=sin^{-1}(\frac{5sin(70)}{5.7})\)

 

I do hope the math is correct.

 

From here, you can just plug it in!

 

I hope you did take away something from my answer!

 

-TheLovely1

 Jul 26, 2020
edited by TheLovely1  Jul 26, 2020

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