Let us start with the original equation:
(2a−1)3
Splitting it up, or making it easier, we should put it into:
(2a−1)(2a−1)(2a−1)
Multiplying the first two,:
(4a2−2a−2a+1)(2a−1)
Simplifying and Mathifying:
(4a2−4a+1)(2a−1)=(8a3−4a2−8a2+4a+2a−1)=(8a3−12a2+6a−1)
So in the end, the answer is:
(8a^3-12a^2+6a-1)
