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In square ABCD, AD is four centimeters, and M is the midpoint of CD. Let O be the intersection of AC and BM. What is the ratio of OC to OA? Express your answer as a common fraction.

 

Work:

...

I drew the picture?

...

I labeled AD, DC, CB, and BA as 4...

 

I honestly don't know what to do here...

 Dec 8, 2019
 #1
avatar+188 
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i made a square too. 

for me, AC split through the center of the square, so AC=4sqrt2 by a^2+b^2=c^2. now that you know the length, can you take it from here? because i got stuck after that :( 

 

well actually we also know that BM=2sqrt5 by the same theorem above, but that's all i've got :'(

 Dec 8, 2019
 #2
avatar+1692 
+2

Oof I was just going to change it to AC equals 4 sqrt2 and BM equals 2 sqrt 5, then I saw your hint.

 

I want to know like where the point o is...

 

From there, Maybe I could work it out?

 Dec 8, 2019

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