In square ABCD, AD is four centimeters, and M is the midpoint of CD. Let O be the intersection of AC and BM. What is the ratio of OC to OA? Express your answer as a common fraction.

Work:

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I drew the picture?

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I labeled AD, DC, CB, and BA as 4...

I honestly don't know what to do here...

tommarvoloriddle Dec 8, 2019

#1**+2 **

i made a square too.

for me, AC split through the center of the square, so AC=4sqrt2 by a^2+b^2=c^2. now that you know the length, can you take it from here? because i got stuck after that :(

well actually we also know that BM=2sqrt5 by the same theorem above, but that's all i've got :'(

atlas9 Dec 8, 2019

#2**+2 **

Oof I was just going to change it to AC equals 4 sqrt2 and BM equals 2 sqrt 5, then I saw your hint.

I want to know like where the point o is...

From there, Maybe I could work it out?

tommarvoloriddle Dec 8, 2019