2(a-5)(a+5)=21a
solve for a.
just so i won't cunfuse you:
2(a-5)(a+5)=(2a-10)(a-5)
that means:
(2a-10)(a-5)=
2a²-10a-10a-50=
2a²-20a-50=
21a
divide both sides by a:
2a-10-(50/a)=21
add 10:
2a-(50/a)=31
divide by two:
a-(25/a)=15.5
multiply by a:
a²-25=15.5/a
subtract 25 and take the square root:
a=sqrt((15.5/a)-25)
idk how to get the rest, but, at least it might help.
any number can!
What do you mean by "i"?
well, this is about GRAM'S NUMBER!!!
I did it because:
It would block out some of my writing, and of course, I would not like that.
Okay :).
No,
\(\pi + \pi = \tau\)
And, jeez, just cool down, it's not like it's the zombie apocolipse!
but, -4 is NOT greater than 1!!!
So is 00 because enything to the power of 0, equals 1, but 0 to the power of anything, equals 0.
So it equals 1 and 0 but you have to give out one scalar, you can't give out two scalars.
THAT IS COMPLETLY RONG!!!!!!!!!!!!!!!!!!!!!!!!!!
THEY WERE TALKING ABOUT A FUNCTION!!!!!!!!!!!!!!!
yup, it's \(\aleph_0.\)
this is the output:
Hi, there!
I was just trying to give out some simple HTML.
No, it's between 1 and -1.
\(0.5=0.5\\ 0.5\times0.5=0.25\\ 0.25\times0.5=0.125\)
\(Answer:\\ 0.125\\ B)\)
\(g(x)=x^2\\ f(x)=x^2-2x=g(x)-g'(x)=g(x)-\frac{d}{dx}g(x)\)
