2(a-5)(a+5)=21a

solve for a.

just so i won't cunfuse you:

2(a-5)(a+5)=(2a-10)(a-5)

that means:

(2a-10)(a-5)=

2a²-10a-10a-50=

2a²-20a-50=

21a

divide both sides by a:

2a-10-(50/a)=21

add 10:

2a-(50/a)=31

divide by two:

a-(25/a)=15.5

multiply by a:

a²-25=15.5/a

subtract 25 and take the square root:

a=sqrt((15.5/a)-25)

idk how to get the rest, but, at least it might help.

any number can!

What do you mean by "i"?

well, this is about GRAM'S NUMBER!!!

I did it because:

It would block out some of my writing, and of course, I would not like that.

Okay :).

No,

\(\pi + \pi = \tau\)

And, jeez, just cool down, it's not like it's the zombie apocolipse!

but, -4 is NOT greater than 1!!!

So is 0^{0} because enything to the power of 0, equals 1, but 0 to the power of anything, equals 0.

So it equals 1 and 0 but you have to give out one scalar, you can't give out two scalars.

THAT IS COMPLETLY RONG!!!!!!!!!!!!!!!!!!!!!!!!!!

THEY WERE TALKING ABOUT A FUNCTION!!!!!!!!!!!!!!!

yup, it's \(\aleph_0.\)

this is the output:

Hi, there!

I was just trying to give out some simple HTML.

No, it's between 1 and ^{-}1.

\(0.5=0.5\\ 0.5\times0.5=0.25\\ 0.25\times0.5=0.125\)

\(Answer:\\ 0.125\\ B)\)

\(g(x)=x^2\\ f(x)=x^2-2x=g(x)-g'(x)=g(x)-\frac{d}{dx}g(x)\)