Will85237

Impulse is the change in momentum. Impulse force is the average force which caused the change in momentum.

It's divisible by 1, 2, 3, 6, 13, 26, 39, and 78.

Some of those are higher than 11.

The next term of the sequence is always equal to the last term multiplied by the common ratio.

a₁ = 2

a₂​ = 2*2 = 4

a₃​ = 4*2 = 8

a₄ = 8*2 = 16

a₅ = 16*2 = 32

If we take the net of the cone, we have an sector with a radius equal to the cone's height, and a circle with a diameter equal to the cone's diameter.

In order to find the angle of the arc, we know that the circle's perimeter must equal the sector's arc.

$P=\pi d$$l=\frac{\theta r}{2}$

$\frac{\theta r}{2}=\pi d$

$\frac{\theta 12}{2}=\pi 10$

$\theta=5.24rad$

Area of circle base:

$A=\pi r^2$

$A=\pi (\frac{10}{2})^2$

$A=78.54$

Area of sector:

$A=\frac{\theta r^2}{2}$

$A=\frac{5.24\times12^2}{2}$

$A=377$

Total area is 456 units²

Subract stuff.

$5E8-7E7$

$4.3E8\space units\space distance$

Or alternatively, you could divide stuff.

$5E8/7E7$

$7.14$

7.14 times as far from the sun.

Multiply stuff.

$-5e(3e^2-e+6)$

$-5e\times3e^2-5e\times(-e)-5e\times6$

$-15e^3+5e^2-30e$

Let's assume the car is driving at 130km/h.

Divide 2,000,300km by this speed, and you get 15,400h or 641 days.

Hopefully you meant 2000.3km, which would take 15.4h, which is less than 1 day.

They are a unit of measurement for an angle. They are defined so that the length of an arc diveded by the radius equals the angle in radians.

The cat's potential energy before jumping is:

$PE=mgh$

$PE=5\times9.81\times3$

$PE=147J$

This will all be transferred to kinetic energy just before the cat hits the floor.

$KE=\frac{mv^2}{2}$

$147=\frac{5v^2}{2}$

$v=7.67m/s$

The formula for kinetic energy is

$KE=\frac{mv^2}{2}$

$1,850=\frac{12v^2}{2}$

$v=17.6m/s$