XxmathguyxX

the guest's were both me i forgot to login lol

1/2 x 1/2 x 1/2 = 1/8

Uh... is it my problem or can i not see the cards

totally forgot alll about that lol

thanks you for reminding me!

\([asy] size(6cm); pair A,B,C,D,O; A=(0,9); D=(12,0); B=(5,5); C=(5,1); draw(A--O^^O--D,dashed); draw(A..(A+B)/2+(0,-1)..B--C); draw(rightanglemark(D,O,A,20)); dot(Label("A",A,N)); dot(Label("B",B,N)); dot(Label("C",C,W)); dot(Label("D",D,E)); dot(Label("O",O,S)); label("9 feet",A--O,W); label("12 feet", D--O,S); label("4 feet",B--C,E) ; [/asy]\)doesn't work

it is 69, to find it

\(\sqrt{4761}= \sqrt{9*529}=3\sqrt{529}\)

now, we know that 20 is close to 529 and only a units digit of 3 can result in a units digit of 9, so

\(3\sqrt{529}=3\sqrt{23^2}=3*23=69\)

\(\sqrt{2}+\sqrt{3}+\left(\frac{1}{2\sqrt{2}+3\sqrt{3}}\right)\)

\(\sqrt{2}+\sqrt{3}+\frac{1}{2\sqrt{2}+3\sqrt{3}}\)

\(\frac{\sqrt{2}\left(2\sqrt{2}+3\sqrt{3}\right)}{2\sqrt{2}+3\sqrt{3}}+\sqrt{3}+\frac{1}{2\sqrt{2}+3\sqrt{3}}\)

\(\frac{\sqrt{2}\left(2\sqrt{2}+3\sqrt{3}\right)}{2\sqrt{2}+3\sqrt{3}}+\frac{\sqrt{3}\left(2\sqrt{2}+3\sqrt{3}\right)}{2\sqrt{2}+3\sqrt{3}}+\frac{1}{2\sqrt{2}+3\sqrt{3}}\)

\(\frac{\sqrt{2}\left(2\sqrt{2}+3\sqrt{3}\right)+\sqrt{3}\left(2\sqrt{2}+3\sqrt{3}\right)+1}{2\sqrt{2}+3\sqrt{3}}\)

\(\frac{14+5\sqrt{6}}{2\sqrt{2}+3\sqrt{3}}\)

\(-\frac{-17\sqrt{2}-22\sqrt{3}}{19}\)

\(\frac{17\sqrt{2}+22\sqrt{3}}{19}\)

17+19+22=58, just the same as proyaop's answer!

\(\frac{1}{\sqrt{2}}+\frac{3}{\sqrt{8}}+\frac{5}{\sqrt{32}}\)

\(\frac{1}{\sqrt{2}}+\frac{3}{2\sqrt{2}}+\frac{5}{4\sqrt{2}} \)

\(\frac{4}{4\sqrt{2}}+\frac{6}{4\sqrt{2}}+\frac{5}{4\sqrt{2}}\)

\(\frac{15}{4\sqrt{2}}\)

hmm........ we got different answers

what does 3 significant figures mean? nvm i got it

i don't think it is possible

imagine 20x/2=240

x=24

but according to the pythagorean theorem, 20^2=24^2+something squared

you can tell something is wrong

i may be wrong, because i am assuming you mean that the area of abc=240

but if the perimeter of abc is 240, thats alos not possible because two sides of a triangle always has to be greater than the other one.