+0  
 
-1
168
3
avatar

As shown in the diagram, one end of a -foot-long electric cable is fixed at point A on the wall, and the other end of the cable (denoted by C) is a sensor. There is a pin attached to the cable at a point B that is 4 units away from C, and the pin can be fixed to any point on the wall reachable by B. Due to gravity, the free part of the cable (i.e. BC) is always perpendicular to the ground OD. A few other measurements are provided in the diagram. What is the minimum distance between C and D? 
 

 

 

(Apparently this is the latex?)

[asy]
size(6cm);

pair A,B,C,D,O;

A=(0,9);
D=(12,0);
B=(5,5);
C=(5,1);

draw(A--O^^O--D,dashed);
draw(A..(A+B)/2+(0,-1)..B--C);
draw(rightanglemark(D,O,A,20));

dot(Label("$A$",A,N));
dot(Label("$B$",B,N));
dot(Label("$C$",C,W));
dot(Label("$D$",D,E));
dot(Label("$O$",O,S));

label("9 feet",A--O,W);
label("12 feet", D--O,S);
label("4 feet",B--C,E) ;
[/asy]

 Feb 2, 2022
 #1
avatar+361 
+3

\([asy] size(6cm); pair A,B,C,D,O; A=(0,9); D=(12,0); B=(5,5); C=(5,1); draw(A--O^^O--D,dashed); draw(A..(A+B)/2+(0,-1)..B--C); draw(rightanglemark(D,O,A,20)); dot(Label("A",A,N)); dot(Label("B",B,N)); dot(Label("C",C,W)); dot(Label("D",D,E)); dot(Label("O",O,S)); label("9 feet",A--O,W); label("12 feet", D--O,S); label("4 feet",B--C,E) ; [/asy]\)doesn't work

 Feb 2, 2022
 #2
avatar
0

Here you go!

Guest Feb 2, 2022
 #3
avatar+13883 
+1

Hello Guest!

 

There you will find the solution:

https://web2.0calc.com/questions/geometry_73561

laugh  !

 Feb 2, 2022

39 Online Users

avatar
avatar
avatar