XxmathguyxX

9*5*7*11*13=45045

45045-1=45044

so 33 percent is 33/100

8*100/33*1/5=800/33*1/5=800/165

um....

this is unsolvable.........................

WAITWAITWAIT

are you cheating?!?!?

there is a (1point) and that is usually on tests. If you are trying to cheat on a test plz don't!

Ahhh... ok

so a 10percent chance to hit one target.

so if he tries ten times, there is a 10x10=100 percent chance that he will hit a target

so 100 percent.

I acually have no idea how to do this problem...

I'll give it my best shot.

I honestly couldn't find any other way than 18+2 =20

so 20?

I am most definently wrong

anybody help?

It would be three

@asinus it is not 1 because 1 is not prime

why does this look like a test at your school?

If I am wrong, good, but if I am right, plz don't cheat!

Ok, I am giving you the benifit of the doubt

it is. the second one 

remove the parenthesis and you will see the answer

what does 0.10.10,point,1 mean?

waitwaitwait.

\(\sqrt125\)

\(5\sqrt5\)

oops. um...

By division we find that 𝑛3+100=(𝑛+10)(𝑛2−10𝑛+100)−900n3+100=(n+10)(n2−10n+100)−900.

Therefore, if 𝑛+10n+10 divides 𝑛3+100n3+100, then it must also divide 900. Since we are looking for largest 𝑛n, 𝑛n is maximized whenever 𝑛+10n+10 is, and since the largest divisor of 900 is 900, we must have 𝑛+10=900⇒𝑛=890n+10=900⇒n=890

The largest 𝑛 is therefore 890

ok so the n3 and n2 is just \(n^3 or N^2\)