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19.      12² + b²  = 20²

 

20.     5²  +  10²   =   25   + 100  = 125 = c²           ( 'c' then = sqrt (125)  )

ok,

According to the Pythagorean Thereom,

\(12^2+b^2=20^2\)

\(144+b^2=400\)

\(b^2=256\)

\(b=16\)

This is for 19.

 

 

 \(25+100=125\)

\(\sqrt125=15\)

so 15 for number 20

waitwaitwait.

\(\sqrt125\)

\(5\sqrt5\)

oops. um...