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yes always.....happy took my place just by comments!

this time is an advantage!

no tomorrow will be worse....whole day studying.......me-dying 

iken tutok intekrálni puzi

Yes :)

 log 3.000 = log3

 log 30.00 = log(10*3)=log10+log3=1+log3

 log 300.00= log(100*3)=log100+log3=2+log3

 log 3000= log(1000*3)=log1000+log3=3+log3

 log (3 x 10^12)= log(10^12*3)=log10^12+log3=1,000,000,000,000+log3

(0.0042) (280,000)/4,900,000=

(4.2 x 10^-3) (2.8 x 10⁵)/ (4.9 x 10⁶) =

(4.2)(2.8)/(4.9) x 10^-3 x 10⁵ x 10^-6=

(4.2)(2.8)/(4.9) x 10^-4

2.4 x 10^-4

Sometimes it is tough being a kid.  

This type of thing happens to adults in their work places sometimes too.

It is never fun.  

BUT tomorrow will be better.    

$$\\\frac{5.12}{x} = \frac{.25}{.02}\\\\
$When I get entire fractions on both sides and x is on the bottom I just turn both sides upside down$\\\\
\\\frac{x}{5.12} = \frac{.02}{.25}\\\\
$now multiply both sides by 5.12$$$

Don't feel bad, rosala...I agree...the more help...the better!!!!

[Plus....getting those points is ALWAYS a good thing  !!! ]

(0.0042) (280,000)/4,900,000

$$\\=\frac{42*10^{-4}\;\;\times\;\;28*10^4}{49*10^5}\\\\
$divide top and bottom by 7$\\\\
=\frac{6*10^{-4}\;\;\times\;\;28*10^4}{7*10^5}\\\\
$divide top and bottom by 7 again$\\\\
=\frac{6*10^{-4}\;\;\times\;\;4*10^4}{10^5}\\\\
=\frac{6*4*10^{-4}*10^4}{10^5}\\\\
=\frac{24*10^{-4+4}}{10^5}\\\\
=\frac{24}{100000}\\\\
or\\\\
=24*10^{-5}\\\\
=2.4*10^1*10^{-5}\\\\
=2.4*10^{-4}$$

My answer is different from what you were expecting - I cannot spot a mistake bur maybe someone else can 

Sorry CPhill but the question is about my dear score place so i have to answer this and also this is to help anon more nicely!

so we'll do it like

1 2/3  ÷ 60/1

(3*1+2)

=5/3  ÷  60/1

(now we will turn division into multiplication and also reciprocate the right fraction)

=5/3 * 1/60

now we will cut or reduce the following and when can no more reduce then will will simply multiply!

=1/3 * 1/12

= 1/36 ANSWER

CPhill pls dont mind if i answer your answered questions or anyone elses answered!

the more help is there, the better understanding occurs!

Take a look at this  :)

3a+4a-(5x3)÷2

=3a+4a-15÷2

=3a+4a-7.5

=7a-7.5

$$\\6x^2+7-2x-3x^2-5x+1\\
6x^2-3x^2-2x-5x+1+7\\$$

you can add (or subtract) your  $$x^2$$   terms

you can add (or subtract) your  $$x$$   terms

you can add (or subtract) your  constants   

You try - post your answer and we will tell you if it is correct :)

39 = 3 x 13

.

(.08*(.75))/ (1-.08*(.75))

Now put it straight into the web2calc on the home page :)

As a slight tweak to the problem, suppose the question was "what is the probability that at least one black ball is drawn in three b***s?"

Prob that 1st ball is non-black = 6/9

Prob that next ball is non-black = 5/8

Prob that final ball is non-black = 4/7

So probability of at least 1 black ball = 1 - 6*5*4/(9*8*7) = 16/21

Using DavidQD and Chris's values above:  Probability of at least 1 black ball = 64/84 = 16/21

Using my answer to the original problem:  Probability of at least 1 black ball = 384/504 = 16/21

.

[x/(x-8)]+8=[8/(x-8)]

The easiest way to do this is to subtract [x/(x-8)] from both sides and write 8 as 8/1.....so we have

8/1 =[8/(x-8)] - [x/(x-8)] =

8/1 = (8 - x)/(x-8)    but the right side = -(x -8)/ (x-8) = -1

And 8 can never = -1   .....so this has no solution

1 + 2/3 = 5/3

So we have

5/3  /  60/1

Remember, that when we divide fractions, we change to multiplication and "flip" the second fraction.....

You should be able to take it from there

S = .90pr   where S = the sales tax

Just key in ".5" and hit the "=" sign.

its 24 000 smeg head

(-3x^2)(5x^-3)

$$\\(-3x^2)(5x^{-3})\\
=-3x^2\;\;*\;\;5x^{-3}\\
=-3*5*x^2*x^{-3}\\
=-15*x^{2-3}\\
=-15x^{-1}\\
or\\
=-\frac{15}{x}$$

These answers all have the same decimal part .....the only diffenence is in the integer part of their evaluation. The integer part tells us the exponent on "10" when we write the given antilog in scientific notation.

Thus

3 = 10^.477 = 3 x 10^0

30 = 10^1.477 = 3 x 10^1

etc.