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History but riddles are fine for me here

Mabey

your life

Calc apollogies

What is that? "New Math"?

1/ -0.25 = - 4

Solve for x:
y = 0.0629 x^2-0.2765 x+0.3093

0.0629 x^2-0.2765 x+0.3093 = (629 x^2)/10000-(553 x)/2000+3093/10000:
y = (629 x^2)/10000-(553 x)/2000+3093/10000

y = (629 x^2)/10000-(553 x)/2000+3093/10000 is equivalent to (629 x^2)/10000-(553 x)/2000+3093/10000 = y:
(629 x^2)/10000-(553 x)/2000+3093/10000 = y

Multiply both sides by 10000/629:
x^2-(2765 x)/629+3093/629 = (10000 y)/629

Subtract 3093/629 from both sides:
x^2-(2765 x)/629 = (10000 y)/629-3093/629

Add 7645225/1582564 to both sides:
x^2-(2765 x)/629+7645225/1582564 = (10000 y)/629-136763/1582564

Write the left hand side as a square:
(x-2765/1258)^2 = (10000 y)/629-136763/1582564

Take the square root of both sides:
x-2765/1258 = sqrt((10000 y)/629-136763/1582564) or x-2765/1258 = -sqrt((10000 y)/629-136763/1582564)

Add 2765/1258 to both sides:
x = 2765/1258+sqrt((10000 y)/(629)-(136763)/1582564) or x-2765/1258 = -sqrt((10000 y)/629-136763/1582564)

Add 2765/1258 to both sides:
Answer: |x = 2765/1258+sqrt((10000 y)/(629)-(136763)/1582564)    or    x = 2765/1258-sqrt((10000 y)/(629)-(136763)/1582564)

? I'm not Im just being nice and wishing him a Happy Birthday!

y = 0.0629x2 - 0.2765x + 0.3093 = 0  then x=?

\(0.0629 x^{2} - 0.2765x + 0.3093=0 \)

       a                     b                  c

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(x = {0.2765 \pm \sqrt{0.2765^2-4\times 0.0629\times0.3093} \over 2\times0.0629}\)

\({\color{blue}x=\frac{0.2765\pm\sqrt{\color{red}-0.00136763}}{2\times0.0629}}\)

\({\color{blue}The \ equation \ has \ no \ real \ solution.}\)

dont be a werdo

dont be a werdo

You can get x, but only in terms of y!!.

denominators are denominator idiot

n, n+1, n+2

2[n+n+1] < 3[n+2], solve for n

n < 4 . This could apply to:

1, 2, 3 OR 2, 3, 4 OR 3, 4, 5

at 4, 5, 6 both sides will be equal. You made this one up yourself, didn't you?