128.8 / 8 = 16.1 cm
(55/4) (8/5) =
(55/5) (8/4) =
11 * 2 =
22
Find the side of a square
s^2 + (2s)^2 = 20
5s^2 = 20
s^2 = 4
s = 2
So
AC^2 = s^2 + (3s)^2
AC^2 = 2^2 + 6^2
AC^2 = 4 + 36
AC^2 = 40
AC = √ 40 = 2√10 cm
Area = B * H / 2 = (9 + 1/2) (5) / 2 = (19/2)(5/2) = 95/4 = 23.75 units^2
I assume you mean
if a = -3 and b = -9, what is 6ab-14a^2
6(-3)(-9) - 14(-3)^2 =
162 - 126 =
36
In triangle ABC, A = 40°, B = 80°, C = 60°, and side AB = 12. Find sides AC and BC.
12/sin 60 = AC/sin 80
AC = 12*sin 80/sin 60 ≈ 13.646
12/sin 60 = BC / sin 40
BC = 12*sin(40)/sin(60) ≈ 8.907
(5x + 7)(3) - (x+2) =
15x + 21 - x - 2 =
14x + 19
I believe f(x) = −6x^2
f(x) for x = 0 ..... f(0) = 0 g(0) = −1 true
f(x) for x = − 6 ..... f(−6) = −216 g(−6) = −61 false
g(x) for x = 2 .... f(2) = −24 g(2) = 3 true
g(x) for x = 3 .... f(3) = −54 g(2) = 2 true
LOL!!!!.......mabe he/she really wants the steps for "sin," EP.....!!!!
