O = (3, −2)
S = (−2, 4)
distance = 5√ [ ( −2 −3)^2 + ( −2 −4)^2] = 5 √[ 25 + 36] = 5√61 ≈ 39 miles
"about 40" seems closest
P = ( −2, 8)
Q = ( 8, −4)
Midpoint :
[ ( −2 + 8) / 2 , (−4 + 8) / 2 ] = [ 3, 2]
1909s "vdb" ????
Here : https://coins.thefuntimesguide.com/1909_s_vdb_penny-2/
x = dogs
x + 7 = cats
dogs + cats = 45
x + ( x + 7) = 45
2x + 7 = 45 subtract 7 from both sides
2x = 38 divide both sides by 2
x = 19 = dogs x + 7 = 19 + 7 = 26 = cats
Possibilities
(1,5) (5,1)
(2,5) (5,2)
(3,5) (5,3)
(4,5) (5,4)
(5,5)
(5,6) (6,5) = 11
Total Possibillities = 36
Probability = 11/ 36
C = (5/9) ( F − 32)
(1/2) ( 6 + 1/4) (2 + 1/4) =
(1/2) (25 / 4) ( 9 / 4) =
225 / 32
Use the inverse cosine
arccos (8/13) = y ≈ 52.02°
