CPhill

( x + 2) / (x^2 - 2x - 24 )  =

( x + 2)  / [ (x - 6) (x + 4 ) ]

The domain  is   ( - inf , - 4) ∪ ( - 4, 6) ∪ (6 ,inf)

Graph :

arccos ( 7.5 / 22.3)  ≈ 70.35°

Divide 58  by 10   = 5 + 8/10   =  5 + 4/5

The nth term is given by :     4 * 5^{n- 1} ...so.... 

4 * 5^{(10 - 1)}  = 4 * 5⁹ = 7,812,500

(x-4)/6    =     (x+5)/5 = -50

              ↑

What is the sign beween the fractions suppposed to be???

9x + 1/2y = 51   →  18x + y = 102    →  -18x -  y = - 102    (1)

7x + 1/3y = 39   →  21x + y = 117    →   21x + y =    117    (2)

Add (1) to (2)  and we have

3x  = 15    →   x  = 5

So

18(5)  + y  =  102

90 + y  = 102        →  y  = 12

y=(2-x)^2+5  →   y=(x-2)^2+5

The vertex is at (2, 5)......the "parent" graph of y = x^2  has its verex at (0, 0)...so the given graph is transformed to the right 2 units and up 5 units

a. The volume of the composite solid  =  x^3  + 4 * 4 * x  =[ x^3  + 16x^2] inches^3

b.  25x^2  = x^3 +  16x^2    subtract 25x^2 from both sides

0 = x^3  -  9x^2     factor

0  = x^2 (x - 9)     set both factors to 0 and solve for x..... and x  = 0 [reject]  or x = 9 in

Setting the polynomial in part (a) equal to ____  and solving for x results in x=__ , x=__, x=__

                                                                   25x^2                                                0        0         9

- 5  = -.5x^2+x+4   multiply through by -2

10  = x^2 - 2x - 8    subtract 10 from both sides

0 = x^2 - 2x - 18   using the quad formula, the solutions  are

x =  1 - √19     and     x =  1 + √19 

C(16, 4)   = 1820 ways