CPhill

Note :   88 ft/sec  = 60 mph  .....so.....

75 mph  = [ 88 ft/sec  / 60 mph]  = 110 ft / sec

So

165 ft / [110 ft / sec]  =

1.5 sec   = reaction time

√180  =

√[ 36 * 5  ]  =

√ 36  * √5  =

6√5

Thanks for the correction, Obscure.....my bad....!!!!

(6a)^4  = 6^4 * a^4  =  1296 a^4

Min read so far :

26 + 39 + 38  = 103

Min left to read =

180 - 103  =  77

The  nth term of the sequence is given by : 3*2^(k-1)

a₁  = 3    a₂  = 6     a₄  = 24

So......

3*2^(k-1) >  80

2^(k-1) >  80/3

k - 1  >    log ( 80 / 3)  / log (2)

k  >     log ( 80 / 3)  / log (2) + 1

k > 5.737

So  k  = 6  ...and 3*2(6 - 1)   = 96

1. Find the mean (average)

[79+ 82 + 84 + 81 + 77+ 85+ 82+ 80+ 78+ 83 ]  / 10    =   81.1

2. Find the difference between each data value and the mean and take the absolute value of each difference

abs [79 - 81.1] = 2.1

abs [82 - 81.1] = .9

abs [84 - 81.1] = 2.9

abs [81 - 81.1] = .1

abs [77 - 81.1] =  4.1

abs [82 - 81.1] = .9

abs [85 - 81.1] = 3.9

abs [80 - 81.1] = 1.1

abs [78 - 81.1] = 3.1

abs [83 - 81.1] = 1.9

4. Find the mean (average) of these differences

[ 2.1 + .9 + 2.9 + .1 + 4.1 + .9 + 3.9 + 1.1 + 3.1 + 1.9 ] / 10  =  2.1  = MAD

4y-(-2y-3)=9      simplify

4y + 2y + 3 = 9

6y + 3  = 9      subtract 3 from both sides

6y  = 6        divide both sides by  6

y  = 1

(2-3i)^4  =

2^4  - 4 (2)^3 (3i) + 6 (2)^2 (3i)^2  - 4(2)(3i)^3 + (3i) ^4  =

16 - 96i + 216i^2 - 216i* i^2  + 81  =

97 - 96i - 216 + 216i  =

-119 +  120 i

x^4 + 4x - 7 + 4x^2*y^2*z^3 = ???

x = 3

y = 1.5

z = 7

3^4 + 4(3)  - 7 + 4 * (3)^2 * (1.5)^2 * (7)^3  =

81 + 12 - 7 + 4 * (9) * (2.25) * ( 343)   =

86 + [ 36 * 771.75 ]   =

27,869