is this a possibility? (2-3i)^4
(2-3i)^4 =
2^4 - 4 (2)^3 (3i) + 6 (2)^2 (3i)^2 - 4(2)(3i)^3 + (3i) ^4 =
16 - 96i + 216i^2 - 216i* i^2 + 81 =
97 - 96i - 216 + 216i =
-119 + 120 i
