That's pretty good......I used to be a high jumper and I could break 6 minutes.....doubt if I could have gone under 5 1/2 though........!!!!!
[BTW.....do you realize that the top marathoners run about 5 minutes per mile, every mile, for 26 straight miles.......that's impossible.....!!!! ]
The area = (1/2) H * (B1 + B2)
In other words....[ the sum of the bases times the height ] / 2
So we have
(1/2) (8) (19 + 11) = 4 (30) = 120 m^2
BTW....here's a cool little app for verifying this
http://www.mathopenref.com/trapezoidarea.html
Here you go......it won't look exactly like the diagram, but it's close enough for you to get the idea
If you need extra explanation, let me know......
Nice detective work, hectictar.....I couldn't figure out what was being asked......
This will be the area of a circle with 75 mi as a radius.....so....the area of coverage =
pi * (75)^2 ≈ 17671.46 square miles
Divide 128 by 4 and see what you get......
sec(A) = -1.0635 take the sec inverse
asec (-1.0635) = A ≈ 160.1°
However.....the larger angle = 360 - 160.1 ≈ 199.9°
64.3 with the "3" repeating = 64 + 1/3
Can you take it from there???
An even function has the property that f(x) = f(-x)
So.....if x = 6, then -x = -6 and we have
f(6) = 8 and f(-6) = 8
So f(x) = f(-x)
sqrt(144) = 12 which is an integer.....and an integer is always rational
