CPhill

The scale factor  of the smaller figure to the larger  is (2/3)

So.....it's volume  is  (scale factor) ^3  =  (2/3)^3   as much as the larger 

So....   (2/3)^3 * 27   = [ 2^3 /  3^3] * 27  =  [ 8 / 27 ] / 27  =    8 in^3

Well....without knowing the question, I couldn't  determine which might be correct...

Divide :

( Number who like bowling )   /  ( Total number in survey)

This will produce a decimal......move the decimal two places to the right and add a " % " sign

Radical form

V  = pi *r^2 * h         divide by  pi * h

 V / (pi * h)   =   r^2     take the square root of both sides

√  [  V / (pi * h) ]    = r

Exponential form

[ V / (pi * h) ] ^ (1/2)  = r 

4356 pi   =  pi * r^2 * 9       divide both sides by 9pi

(4356 pi ) / ( 9 pi)  = r^2

484   =  r^2       take the square root of both sides

22 cm  = r

Triangle A'B'C'   will  be (scale factor)^2  times as large as ABC.....iin other words, 4^2  = 16 times the area......

a + 5 > 8      subtract 5 from both sides

a >  3

Here's the image :  

Just add the sides......that will give you the perimeter

sin (theta)   = cos ( 90 - theta)    ....so

sin (49)    =   cos ( 90 - 49)   =  cos (41)

Angle MNL   = 90

So......LMN   +  MLN   = 90

So

71 +  MLN   =  90       subtract  71 from both sides

MLN   =  19      you were correct !!!!

This is a circle with its center at (-4, -3)  and a radius of 4

Here's the graph  :   https://www.desmos.com/calculator/t761domldm