CPhill

Volume   =  4.5 *  3 * 6   =  81 in^3

A car travelling from Town X to Town Y passed a van halfway.The van was travelling in the opposite direction at a uniform speed of 40 km/h.2.5 hours later,the car reached Town Y and the van was still 25 km from Town X.Find the distance between Town X and Town Y.

Call the car's rate, R

And the rate it travels times the time it travels  =  R * 2.5     =  the halway distance between the towns = (1)

And the rate the van travels (40 km/hr ) times 2.5 hrs  + 25 km  =  (1)

So....setting these equal, we have

R * 2.5    =   40* ( 2.5) + 25   simplify

2.5 R   =  100 + 25

2.5R   = 125   divide both sides by 2.5

R  = 50 km/hr

Then....this the rate of the car........so......the  distance between the towns  =  2* (2.5)* 50 =  250 km

[ (4/5) a^2  ] ^2      apply the outer exponent over both terms in the bracket

(4/5)^2   *  (a^2)^2  =

( 16/25) a^4

log ( 3x + 8)  = 2

In exponential form we have

10^2  =  3x  + 8      

100 = 3x + 8      subtract 8 from both sides

92   =  3x           divide both sides by 3

92/3   = x 

One more "formula" 

Segment area  =

(1/2 ) R^2 (θ) - (1/2) R^2 sin (θ)  =

(1/2) R^2   [ θ -  sin ( θ) ]       where  θ  is the measure - in radians - of the central angle  of the sector

Very nice, hectictar.......!!!

Wherever the graph intersects the x axis will  be a zero at that point

Excellent, X²......!!!!!

You taught me a few things, too.....!!!

Probability of odd  =  3/4

Probability of even  =  1/4

So  (3/4) (1/4)    =   3 / 16    [ the events are independent ]

Probability that less than a "4"  is rolled  =   1/2

Probability of heads  = 1/2

So  ( Probability of < 4  and Heads )  =  (1/2 (1/2)   = 1/4