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Please help! Iḿ stuck! (thereś an image, please open)

ZZZZZZ  May 22, 2017
edited by ZZZZZZ  May 22, 2017

Best Answer 

 #1
avatar+4174 
+2

Here I made a triangle where A is the first sighting, B is the light, and C is the second sighting.

The question is, what is the length of BC ?

 

On this first one, I just focused on the angles.

 

m∠BAC = 107º - 60º   =   47º

measure of the green angle = 180º - 107º   =   73º

 

Since the two vertical lines are parallel and line AC crosses them, we have two parallel lines cut by a transversal. So.. the two green angles are the same.

 

Now let's just look at the second triangle.

We can use law of sines to find BC.

\(\frac{1.5}{\sin 26}=\frac{BC}{\sin 47} \\~\\ \frac{1.5}{\sin 26}*\sin 47 =BC \\~\\ 2.503\text{ km} \approx BC\)

hectictar  May 23, 2017
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3+0 Answers

 #1
avatar+4174 
+2
Best Answer

Here I made a triangle where A is the first sighting, B is the light, and C is the second sighting.

The question is, what is the length of BC ?

 

On this first one, I just focused on the angles.

 

m∠BAC = 107º - 60º   =   47º

measure of the green angle = 180º - 107º   =   73º

 

Since the two vertical lines are parallel and line AC crosses them, we have two parallel lines cut by a transversal. So.. the two green angles are the same.

 

Now let's just look at the second triangle.

We can use law of sines to find BC.

\(\frac{1.5}{\sin 26}=\frac{BC}{\sin 47} \\~\\ \frac{1.5}{\sin 26}*\sin 47 =BC \\~\\ 2.503\text{ km} \approx BC\)

hectictar  May 23, 2017
 #2
avatar+75368 
+2

 

Very nice, hectictar.......!!!

 

 

cool cool cool

CPhill  May 23, 2017
 #3
avatar+312 
+1

thanks hectictar

ZZZZZZ  May 30, 2017

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