+9488 Here I made a triangle where A is the first sighting, B is the light, and C is the second sighting.
The question is, what is the length of BC ?
On this first one, I just focused on the angles.
m∠BAC = 107º - 60º = 47º
measure of the green angle = 180º - 107º = 73º
Since the two vertical lines are parallel and line AC crosses them, we have two parallel lines cut by a transversal. So.. the two green angles are the same.
Now let's just look at the second triangle.
We can use law of sines to find BC.
1.5sin26=BCsin47 1.5sin26∗sin47=BC 2.503 km≈BC
+9488 Here I made a triangle where A is the first sighting, B is the light, and C is the second sighting.
The question is, what is the length of BC ?
On this first one, I just focused on the angles.
m∠BAC = 107º - 60º = 47º
measure of the green angle = 180º - 107º = 73º
Since the two vertical lines are parallel and line AC crosses them, we have two parallel lines cut by a transversal. So.. the two green angles are the same.
Now let's just look at the second triangle.
We can use law of sines to find BC.
1.5sin26=BCsin47 1.5sin26∗sin47=BC 2.503 km≈BC
