CPhill

Correct, MG1......!!!!!

tan^-1 (1.3 / 3.1) = about 22.75°

√-25 =

√(-1 * 25)  =

√(-1) * √25     note ... i^2 = -1    so  .... i  = √-1

i * 5   =

5i

If this number is a multiple of 7 and 3, it must be divisible by 21

So 

384 mod 21   =  6

So...this number must be 

304 - 6 = 378

And 378 factors as.. 2 x 3 x 3 x 3 x 7 =  2 x 3 x 3 x 21

We have :

tan 50  = 305.5 / d     where d is the distance we're trying to find  .....rearranging, we have....

d = 305.5 / tan 50 = about 256.34 ft  = 256 ft to the nearest foot.....

16x^2 - y^2 +16y -128 =0   add 128 to both sides

16x^2 - y^2 +16y  = 128     complete the square on y

16x^2 - (y^2 - 16y + 64) = 128 - 64    simplify

16x^2 - (y - 8)^2  = 64       divide both sides by 64

x^2 / 4  - (y - 8)^2  / 64   = 1

This is a hyperbola with a center of (0, 8)......a = 2 and b = 8...the focal points are at (±√68, 8)

Apparently....they just don't stick well to "forum"  posts......

Here's a hint.....put both solutions back into the original problem....if they "work"....they must be correct  !!!

Ah, Melody.....I think you're making a mountain out of a molehill....LOL!!!