Adonai

A square root is the same as a fractional exponent. 2 to the second power is 4, so what root or fractional exponent would you need to bring 64 down to four. The cube root of 64 is 4, so the fractional exponent must be 1/3, so your answer is 1/3 since 4³=64. To put this into a better perspective, 4²=16, and 16^1/2=4.

Order of operations. When a calculator sees -12², it sees it as 12² * -1 due to order of operations. So it calculates the 12² first and then multiplys it by -1. In order to get the correct answer which is 144, you must use parenthesises and put the -12 inside so it looks like this:(-12²). Hope this helped.

You don't. You honestly don't. I don;t know a single scenario where that thing is helpful or you couldn't use the law of sines or cosines.

This question has already been asked and answered good sir or ma'am.

Believe it or not there are still weirdos who use radians on their calculators 

Divide 19 by the cos of 44 degrees or radians depending on what the problem is. If 44 is in degrees you get 26.4131082293040873, if 44 is in radians you get 19.0029776022525227.

I love these things. We know that y equals 2x-6, and x+y=180. We can subtract x from the second equation to put it in terms of y, giving us y=180-x. Since both equations equal to y, we can set them equal to each other, so we get 2x-6=180-x. If we get all the xs one side and the numbers on the other we get 3x=186. Divide by three and our final answer is x=62.

I think the function they are asking for is that of the midline.

-3 and -18 good sir or ma'am.

Ok so the height varies between 2 and 8 feet, so the amplitude is the heighest point minus the lowest, so the amplitude is 6ft. Your period is 16hrs as long as your x axis is in terms of time, and the midline would be y= the midpoint of the min and max height, which in this case is 3ft.

Ok get ready because this might get complicated. A quadrilateral has four sides. A kite has four sides. Therefore, a kite is a quadrilateral. Mind. Blown.

Nevermind I realize now that there was information given that I missed that would be used to find the pressure.