+0  
 
0
3150
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avatar+120 

The Saginaw Bay tides vary between 2 feet and 8 feet. The tide is at its lowest point when time (t) is 0 and completes a full cycle in 16 hours. What is the amplitude, period, and midline of a function that would model this periodic phenomenon?

 Apr 6, 2016

Best Answer 

 #4
avatar+129852 
+5

Correction to a mis-type on my answer....the function should be :

 

h(t)  = 3sin [ (pi/8)t - pi/2 ] + 5

 

And,of course, the amplitude is 3, not 4......!!!!!

 

 

cool cool cool

 Apr 6, 2016
 #1
avatar+124 
+5

Ok so the height varies between 2 and 8 feet, so the amplitude is the heighest point minus the lowest, so the amplitude is 6ft. Your period is 16hrs as long as your x axis is in terms of time, and the midline would be y= the midpoint of the min and max height, which in this case is 3ft.

 Apr 6, 2016
 #2
avatar+129852 
+5

A possible function is given by :

 

h(t)  = 4sin [ (pi/8)t - pi/2 ] + 5

 

The amplitude is 4, the period is 16 radians  ....[ 1 rad  = 1 hour]

 

The midline is given by :

 

h(t)   = 5

 

Here's the graph of both functions :   https://www.desmos.com/calculator/ic00n0hnlr

 

 

 

cool cool cool

 Apr 6, 2016
 #3
avatar+124 
0

I think the function they are asking for is that of the midline.

Adonai  Apr 6, 2016
 #4
avatar+129852 
+5
Best Answer

Correction to a mis-type on my answer....the function should be :

 

h(t)  = 3sin [ (pi/8)t - pi/2 ] + 5

 

And,of course, the amplitude is 3, not 4......!!!!!

 

 

cool cool cool

CPhill Apr 6, 2016

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