aftenn

21 Questions
3 Answers

0

843

2

+78

Solve sqrt(3x+1)=3^sqrt(9x-1) Please describe step by step

Solve sqrt(3x+1)=3^sqrt(9x-1) Please describe step by step

aftenn Aug 23, 2016

0

819

2

+78

Solve sqrt(3x+1)=^3sqrt(9x-1) Please describe step by step

Solve sqrt(3x+1)=^3sqrt(9x-1) Please describe step by step

aftenn Aug 23, 2016

0

901

12

+78

M(t)=85e^(-t/719) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/6 of the

M(t)=85e^(-t/719) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/6 of the original ? The response can be written as t = a ln b where a and b are integers and a = 1 read more ..

MaxWong ●●●●●●●●●●●●

aftenn Aug 22, 2016

0

889

1

+78

Solve (e^x+5)/(9e^-x+4)=2

Solve (e^x+5)/(9e^-x+4)=2
x=lna

aftenn Aug 22, 2016

0

811

3

+78

(e^x+5)/(9e^-x+4)=2

(e^x+5)/(9e^-x+4)=2

aftenn Aug 22, 2016

0

776

3

+78

Please help!

M(t)=85e^(-t/719) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/6 of the original ? The response can be written as t=alnb where a and b are integers and a=1 read more ..

aftenn Aug 22, 2016

0

878

2

+78

solve (e^x+3)/(4e^-x+5)=2

solve (e^x+3)/(4e^-x+5)=2
x=lna

aftenn Aug 22, 2016

0

844

9

+78

m(t)=85e^(-t/29) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/10 of

m(t)=85e^(-t/29) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/10 of the original ? The response can be written as t=alnb where a and b are integers and a=1 read more ..

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aftenn Aug 22, 2016

0

692

2

+78

m(t)=85e^(-t/409) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/6 of the

m(t)=85e^(-t/409) describes the amount of a radioactive isotope as a function of time t [ years]. After how long the amount has dropped to 1/6 of the original ? The response can be written as t=alnb where a and b are integers and a=1 read more ..

aftenn Aug 22, 2016

0

1208

2

+78

log(base 2)16=8 true or false?

log(base 2)16=8 true or false?
log(base 4)2=1/2 true or false?
2log(base 2)^47=47 true or false?
log(base 3)9 + log(base3)1/27=1/2 true or false? read more ..

aftenn Aug 19, 2016

+78

0

i meant 3^

aftennAug 23, 2016

+78

0

log(base 2)16=8 true or false?

log(base 4)2=1/2 true or false?

2log(base 2)^47=47 true or false?

log(base 3)9 + log(base3)1/27=1/2 true or false?

help

aftennAug 19, 2016

+78

0

no i can't.... :(

aftennJul 20, 2016