+78 Determine the coefficients in front x and x^3 (x^2+9x+3)(x^3-4x+7/x)
+129850 (x^2+9x+3)(x^3-4x+7/x) =
x^5 + 9 x^4 - x^3 - 36 x^2 - 5 x + 21/x + 63
I assume you can take it from here
Simplify the following:
(x^2+9 x+3) (x^3-4 x+7/x)
Put each term in x^3-4 x+7/x over the common denominator x: x^3-4 x+7/x = x^4/x-(4 x^2)/x+7/x:
x^4/x-(4 x^2)/x+7/x (x^2+9 x+3)
x^4/x-(4 x^2)/x+7/x = (x^4-4 x^2+7)/x:
Answer: | (x^4 - 4x^2 + 7)/x (x^2 + 9x + 3)=x^5 + 9x^4 - x^3 - 36x^2 - 5x + 21/x + 63
