Alan

We have:  \(17\frac{5}{8}=-2(x+15)\)

Express the left-hand side as an improper fraction: \(\frac{141}{8}=-2(x+15)\)

Divide both sides by -2:   \(x+15=-\frac{141}{16}\)

Subtract 15 from both sides:  \(x =-15-\frac{141}{16}=-23\frac{13}{16}\)

Find them like so:

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Yes!

I would say none of the given answers!

Firstly, it's not very linear.

Secondly, if we do assume a best-fit linear equation the result is dollars = 1.033*(years after 1998) + 25.29

Thirdly, even if we assume a particular functional form over the given years, extrapolating for a further 11 years is way too far!!

The domain is the set of valid values on the x-axis and the range is the corresponding set of valid values on the y-axis.

Another way of looking at this is as follows:

If you start with N0, then after 1 day you are left with 0.98*N0

After 2 days you are left with 0.98^2*N0

After 3 days you are left with 0.98^3*N0

...

After t days you are left with 0.98^t*N0

For t to be the half-life you must have 0.98^t*N0 = N0/2

Divide by N0 and take logs of both sides:

ln(0.98^t) = ln(1/2)

t*ln(0.98) = ln(1/2)

t = ln(1/2)/ln(0.98) ≈ 34.3 days

Divide both sides by pi:   R^2 = A/pi

Take the square root of both sides R = (A/pi)^0.5

Mathematically, there is also R = -(A/pi)^0.5, but if, A and R refer to circles, with R as the radius, then only the positive solution is valid.

There aren't any Real values for x that satisfy this equality:

The following Imaginary numbers satisfy it:  i(2n-1)*pi/2  where n is an integer.

I'll assume this is \(17332.50=Ko(1+0.35)^6\)

If so, then divide both sides by 1.35^6 to get Ko = 17332.5/6.05344514  or Ko ≈ 2863.25

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Google translation:

"John ran his car 250 km in 3 hours and claims not exceeded all the way 80 km per hour; it is false or true, why?"

It is false, because at 80 km/hr (or less) for 3 hours John would only have travelled 80*3 = 240 km (or less), so he must have exceeded 80km/hr at some point to have travelled 250 km in 3 hours.

Google translation:

"Es falso, porque en 80 km / h (o menos) durante 3 horas John solamente habría viajado 80 * 3 = 240 km (o menos), por lo que debe haber superado los 80 km / hr en algún momento de haber viajado 250 km en 3 horas."