Linear equations represent straight lines, so they (i) cross in a single point - one solution, or (ii) they are parallel but apart - no solutions, or (iii) they lie on top of each other - an infinite number of solutions.
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Now that I've used a LaTeX box in my reply, the original question seems to be displayed properly.
Weird!!
I suggest you put your LaTeX in the LaTeX box - select the \(\sum \text{LaTeX}\) Icon on the menu bar of the input page.
You don't need the $$ symbols when you do this.
Junior staff numbers = 28*2/(2+5) → 8
A. B.
1. 5. ncr(6,5) = 6!/(5!1!) → 6
2. 4. ncr(6,4) = 6!/(4!2!) → 15
3. 3. ncr(6,3) = 6!/(3!3!) → 20
4. 2. ncr(6,2) = 6!/(2!4!) → 15
5. 1. ncr(6,1) = 6!/(1!5!) → 6
Total = 62
The sum of i^3 from 1 to n is (n^2(n+1)^2)/4
Multiply this by 5/n^5 to get: S(n) = (5(n+1)^2)/(4n^3)
As n → infinity S(n) → 0
Yes.
H = 3B
H + 12 = 2(B + 12) so 3B + 12 = 2(B + 12)
→ 3B + 12 = 2B + 24
→ B = 12
Bob is 12. (Hank is 36)
Geometrically, in 2 dimensions i and j represent unit length vectors in the x and y directions respectively. In 3 dimensions k represents the unit vector in the z direction. The norm is the square root of the sum of the squared components (the coefficients of i, j and k), and gives the length of the vector.
Correct.
+33667 