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rewrite 

 

n

E   5i^3 / n^5

i=1

as a rational function S(n) and find lim S(n)

 

a. S(n) = n^2(n+1)^2 / 20, lim n-> infinity s(n) = 0

b. S(n) = 5(n+1)^2 / 4n^3, the limit does not exist

c. S(n) = 5(n+1)^2 / 4n^2, lim n-> infinity S(n) = 5/4

d. S(n) = 5n^2(n+1)^2 / 4, lim n-> infinity S(n) = 5

e. S(n) = 5(n+1)^2 / 4n^3, lim n-> infinity S(n) = 0

 Aug 31, 2016
 #1
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The sum of i^3 from 1 to n is (n^2(n+1)^2)/4

 

Multiply this by 5/n^5 to get: S(n) = (5(n+1)^2)/(4n^3)

 

As n → infinity  S(n) → 0

 Aug 31, 2016

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