In how many ways can six different coins be dividd between two students so that each student recieves at least one coin? (the correct answer is 62 but I don't know the method to finding it) Thank you for the help!
A. B.
1. 5. ncr(6,5) = 6!/(5!1!) → 6
2. 4. ncr(6,4) = 6!/(4!2!) → 15
3. 3. ncr(6,3) = 6!/(3!3!) → 20
4. 2. ncr(6,2) = 6!/(2!4!) → 15
5. 1. ncr(6,1) = 6!/(1!5!) → 6
Total = 62
.
