Hallo Gast,
danke für das Danke,
asinus :- ) !
What is 17/2 lb and 3/4 gal as a unit rate?
\(\frac{\frac{17}{2}lb}{\frac{3}{4}gal}=11{\frac{1}{3}}\frac{lb}{gal}\)
\(\large11{\frac{1}{3}}\frac{lb}{gal}\)\(\times\)\(\LARGE\frac{\frac{1kg}{m^3}}{\LARGE\frac{0.010022413122466\ lb}{gal}}\)
\(11{\frac{1}{3}}\frac{lb}{gal}\) \(=1130.79885999\ \frac{kg}{m^3}\)
\(Density \ of \ air \ at \ 1013 \ hPa \ and \approx 100grd \ Celsius.\)
!
20-20e^(-0.1*10)-15
Ergebnis soll -2.36 sein?
\(Es \ heißt \ besser \ Rechenfolge, \ nicht \ Gleichung.\)
\(20-20e^{-0,1*10}-15\)
gleichrangiges subtrahieren, multiplizieren
\(=5-20e^{-1}\)
\(e^{-1}=\frac{1}{e}\)
\(=5-\frac{20}{e}\)
\(=5-7.3575888\)
\(=-2,3575888\) !
(x-6)²=X²+18
Antwort siehe vorige Frage. !
\(x^2-12x+36=x^2+18\) [beidseits -x²
\(-12x=18-36\) [ /(-12)
\(x=\frac{18-36}{-12}\) [subtrahieren und kürzen
\(x= \frac{3}{2}\) !
\(\frac{1kg}{m^3}=\frac{0.010022413122466lb}{gal}\)
3x hoch 5
--------------
Wurzel 3 + 4
\(\frac{3x^5}{\sqrt 3+4}\) \(\times \frac{\sqrt 3-4}{\sqrt 3-4 }\)= \(\frac{x^5\times (3\sqrt 3-12)}{3-16}\) = \(-\frac{3\sqrt3-12}{13}x^5\)
\(=\frac{x^5\times (3\sqrt 3-12)}{3-16}\) \(=\frac{12-3\sqrt3}{13}\ x^5\) !
asinus without login
20 power 0.78
\(20^{ 0.78}=10.34673668\) ( Directly on computer )
\(=e^{ln\ 20\times 0.78 }=e^{2.9957\times 0.78}\)
\(=e^{2.33667117337}\)
\(=10.3467366799\)
If i'm 13 years old, how old i will be in 2061?
\(Life \ age=(2061-2016)years+13years=58years\)
Find the distance a between the points C(−6, 5) and D(−3, 1)
\(a^2=(y_c-y_d)^2+(x_c-x_d)^2\)
\(a^2=(5-1)^2+(-6-(-3))^2\)
\(a^2=4^2+(-3)^2=16+9=25\)
\(a=\sqrt {25}\)
\(a=5\)
\(The \ distance \ between \ C \ and \ D \ is \ a= 5\)
!
