asinus

Hallo heureka, warum haben wir unterschiedliche Lösungen? asinus

what is x if 4 + sqrt (x-4) = sqrt (x+14)?

\(4+\sqrt{x-4}=\sqrt{x+14}\)

\(16+8\sqrt{x-4}+x-4=x+14\)

\(8\sqrt{x-4}=x+14-16+4-x\)

\(\sqrt{x-4}=\frac{2}{8}\)

\(x-4=\frac{1}{16}\)

\(x=4\ \frac{1}{16}\)

  !

-1/3 (n + 15) = -2

\(-\frac{1}{3}(n+15)=-2\)

\(-\frac{n}{3}-5=-2\)

\(-\frac{n}{3}=3\)

\(n=-9\)

  !

1/2(5+10)20=

\(\frac{1}{2}(5+10)^{20}=\frac{1}{2}\times 15^{20}=1.66262836504\times 10^{23}\)

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Assume the Pacific Ocean has a surface area of 1.2 x 108 km2 and an average depth of 3700 m. If the volume of ocean water (4.44*10^22) contains 3.7 percent sodium chloride ("salt") by mass and the density of the water is 1.46 g/mL, calculate the total mass of sodium chloride. (1 ton = 2000 lb, 1 lb = 453.6 g). Calculate the mass of sodium chloride in kg.

\(The \ density \ of \ the \ pure \ water \ is \ 1.00\ g/ml. \)

So

\(m_{salt}=4.44\times 10^{22}l\times \frac{0.46kg\ salt}{l}=2.0424\times 10^{22}kg\ salt\)

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Assume the Pacific Ocean has a surface area of 1.2 x 108 km2 and an average depth of 3700 m. Calculate the volume in Liters.

\(V=A_s\times d_a=1.2\times 10^8km^2\times 3700m\)

.                        \(\large\times \frac{10^6m^2}{km^2}\times \frac{10^3l}{m^3}=4.44\times 10^{20} l\)

                                        !

(1/2)x -17(2/3 . x18) - (2/3)x + 4 <= 1   was ist x?

\(\frac{1}{2}x-17(\frac{2}{3}x^{18})-\frac{2}{3}x+4\leq 1\)       \(\Large So \ gemeint\ ?\)

                                                                   \(Bitte \ melden\ !!\)

\(\frac{1}{2}x-\frac{53}{3}x^{18}-\frac{2}{3}x+3\leq 0\)

\(\frac{1}{2}x-17(\frac{2}{3}x^{18})-\frac{2}{3}x+4\leq 1\)

\(f(x)=-\frac{1}{6}x-\frac{53}{3}x^{18}+3\leq 0\)

\(x_1= 0,903603089274\)

\(x_2=-0,908675093043\)

\(x\in ( \mathbb R <x_2)\wedge ( \mathbb R>x_1)\)

0.4615384615384616 in decimal form?

Perhaps you mean the scientific presentation?

\(0.4615384615384616=4.615384615384616\times 10^{-1}\)

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wie berechne ich den Marchzins (MZ)

Klicke den Link.

|z−1|+ z = 3−i

z=(7/4)-i              unrichtig!

\(\frac{7}{4}-1+\frac{7}{4}-i=3-i\)

\(\frac{14}{4}-1-i=3-i\)

\((\frac{10}{4}-i)\neq (3-i)\)  q e d

  !