Assume the Pacific Ocean has a surface area of 1.2 x 108 km2 and an average depth of 3700 m. If the volume of ocean water (4.44*10^22) contains 3.7 percent sodium chloride ("salt") by mass and the density of the water is 1.46 g/mL, calculate the total mass of sodium chloride. (1 ton = 2000 lb, 1 lb = 453.6 g). Calculate the mass of sodium chloride in kg.
+37099 Total mass = 4.44 x 10^22 ml x 1.46 gm/ml then multiply this by .037 (3.7%) to get salt mass in GRAMS then divide by 1000 to get KILOgrams
4.44 x 10^22 x 1.46 x .037 / 1000 = .0002398 x 10^22 kg = 2.398 x 10^18 kg sodium chloride
+37099 CORRECTION: VOLUME was in liters not ml as I wrote....answer will be 1000 times greater
Total mass = 4.44 x 10^22 liters x 1.46 gm/ml x 1000ml/l then multiply this by .037 (3.7%) to get salt mass in GRAMS then divide by 1000 to get KILOgrams
4.44 x 10^25 x 1.46 x .037 / 1000 = .0002398 x 10^25 kg = 2.398 x 10^21 kg sodium chloride
+14986 Assume the Pacific Ocean has a surface area of 1.2 x 108 km2 and an average depth of 3700 m. If the volume of ocean water (4.44*10^22) contains 3.7 percent sodium chloride ("salt") by mass and the density of the water is 1.46 g/mL, calculate the total mass of sodium chloride. (1 ton = 2000 lb, 1 lb = 453.6 g). Calculate the mass of sodium chloride in kg.
\(The \ density \ of \ the \ pure \ water \ is \ 1.00\ g/ml. \)
So
\(m_{salt}=4.44\times 10^{22}l\times \frac{0.46kg\ salt}{l}=2.0424\times 10^{22}kg\ salt\)
!
Note: There is an ERROR in the question!!: 1.2 x 10^8 sq.km x 10^6 m x 3,700 m=4.44 x 10^17 Cubic meters x 1,000,000 cubic cm or ml =4.44 x 10^23 cubic cm or ml. Therefore,
The volume of water as he/she has calculated as 4.44 x 10^22 is in error by a factor of 10.
It should be: 4.44 x 10^23 cubic cm, or ml =4.44 x 10^20 Liters. So that:
[4.44 x 10^23 ml x 1.46 g/ml x 3.7%] =2.3985 x 10^23 grams / 1,000 grams =2.3985 x 10^20 Kg.- Total mass of salt.
+37099 Thanx for the error correction.....the ORIGINAL posted question asked for the volume of the ocean which I correctly calculated as 4.44 x 10^20 liters.....then THIS follow-on question INcorrectly stated the volume as 4.44 x 10^22 without volume units! Hence all of the confusion and 'incorrectness' ! Good Eye Guest !
