Atroshus

We try to rewrite the given equation in the standard form for an ellipse. Completing the square in both variables, we have

2(x^2+4x) + (y^2-10y) + c = 0

2(x^2+4x+4) + (y^2-10y+25) + c = 33

2(x+2)^2 + (y-5)^2 = 33-c

we need 2(x+2)^2 + (y-5)^2 to be 0 (degenerate ellipse)

so c=33

x=-1/6

Simplifying F(x) = 5x2 + -20

Multiply F * x xF = 5x2 + -20

Reorder the terms: xF = -20 + 5x2

Solving xF = -20 + 5x2

Solving for variable 'x'.

Reorder the terms: 20 + xF + -5x2 = -20 + 5x2 + 20 + -5x2

Reorder the terms: 20 + xF + -5x2 = -20 + 20 + 5x2 + -5x2

Combine like terms: -20 + 20 = 0 20 + xF + -5x2 = 0 + 5x2 + -5x2 20 + xF + -5x2 = 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0 20 + xF + -5x2 = 0

The solution to this equation could not be determined.

The initial upload limit is 10. But you can increase that limit by earning medals (the more people that give your course a Star ranking will help you earn more medals).

But of course this is kinda off topic. (Not really math)

It would be a D- in letter grade

A = π r^2

A is area

π is pi

r is the radius of the circle

I got 11sqrt3 but it wasn't correct

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half hexagon at the bottom = 3sqrt3

((3sqrt3/2)*2^2)/2

top triangle = 8sqrt3

edge length 2= long diagonal 4 << length from E to C

draw point halfway E to C to create point F

EF=CF=2

pythagorean theorem: DF= 2sqrt3

area of top triangle = DF*4 = 8sqrt3

add up= 10sqrt3

well answered ghosty

what ever equation you put in to get that number just put it in here

https://www.symbolab.com/solver/radical-equation-calculator

im sure they can give you a better number to work with