+0

# Help me

0
84
2

Solve for $x$: $$\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$$

Guest Oct 12, 2017

#2
+648
+2

$$\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$$

First, you can take a 3 out of the numerator on the left.

$$\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$$

Combine like factors on the top right.

$$\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}$$

The x+4's on the right can cancel.

$$3=\frac{12x^2+8x}{2x}$$

The left can be divided by 2x.

$$3=6x+4$$

Subtract 4 from both sides.

$$-1=6x$$

Divide both sides by 6.

$$x=-\frac{1}{6}$$

AdamTaurus  Oct 12, 2017
Sort:

#1
+50
+1

x=-1/6

Atroshus  Oct 12, 2017
#2
+648
+2

$$\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$$

First, you can take a 3 out of the numerator on the left.

$$\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$$

Combine like factors on the top right.

$$\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}$$

The x+4's on the right can cancel.

$$3=\frac{12x^2+8x}{2x}$$

The left can be divided by 2x.

$$3=6x+4$$

Subtract 4 from both sides.

$$-1=6x$$

Divide both sides by 6.

$$x=-\frac{1}{6}$$

AdamTaurus  Oct 12, 2017

### 7 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details