#2**+2 **

\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

First, you can take a 3 out of the numerator on the left.

\(\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

Combine like factors on the top right.

\(\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}\)

The x+4's on the right can cancel.

\(3=\frac{12x^2+8x}{2x}\)

The left can be divided by 2x.

\(3=6x+4\)

Subtract 4 from both sides.

\(-1=6x\)

Divide both sides by 6.

\(x=-\frac{1}{6}\)

AdamTaurus
Oct 12, 2017

#2**+2 **

Best Answer

\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

First, you can take a 3 out of the numerator on the left.

\(\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)

Combine like factors on the top right.

\(\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}\)

The x+4's on the right can cancel.

\(3=\frac{12x^2+8x}{2x}\)

The left can be divided by 2x.

\(3=6x+4\)

Subtract 4 from both sides.

\(-1=6x\)

Divide both sides by 6.

\(x=-\frac{1}{6}\)

AdamTaurus
Oct 12, 2017