\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)
First, you can take a 3 out of the numerator on the left.
\(\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)
Combine like factors on the top right.
\(\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}\)
The x+4's on the right can cancel.
\(3=\frac{12x^2+8x}{2x}\)
The left can be divided by 2x.
\(3=6x+4\)
Subtract 4 from both sides.
\(-1=6x\)
Divide both sides by 6.
\(x=-\frac{1}{6}\)
\(\frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)
First, you can take a 3 out of the numerator on the left.
\(\frac{3(x+4)}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}\)
Combine like factors on the top right.
\(\frac{3(x+4)}{x+4} = \frac{12x^2+8x}{2x}\)
The x+4's on the right can cancel.
\(3=\frac{12x^2+8x}{2x}\)
The left can be divided by 2x.
\(3=6x+4\)
Subtract 4 from both sides.
\(-1=6x\)
Divide both sides by 6.
\(x=-\frac{1}{6}\)