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An ellipse whose axes are parallel to the coordinate axes is tangent to the x-axis at (4,0) and tangent to the y-axis at (0,1) Find the distance between the foci of the ellipse.

 Jan 1, 2020
 #1
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0

The distance between the foci is 6*sqrt(3).

 Jan 1, 2020
 #2
avatar+98 
+1

not correct

Atroshus  Jan 1, 2020
 #3
avatar+106519 
+2

We have something like this  : https://www.desmos.com/calculator/jpriys8xex

 

The equation of the ellipse  is

 

(x - 4)^2          (y - 1)^2

______    +    _______    =   1

   16                     1

 

 

 

The focal  length ,c,  is given  by   √  [ 16 - 1 ]   =  √(15)  =  c

 

So.....the   distance between the  foci   =  2c   = 2 √15   units

 

 

cool cool cool

 Jan 1, 2020
 #4
avatar+98 
+1

omg thx ur a hero :D

Atroshus  Jan 1, 2020
 #5
avatar+106519 
0

LOL......!!!

 

THX.....( I do my best   ...  )

 

cool cool cool

CPhill  Jan 1, 2020

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