An ellipse whose axes are parallel to the coordinate axes is tangent to the x-axis at (4,0) and tangent to the y-axis at (0,1) Find the distance between the foci of the ellipse.
The distance between the foci is 6*sqrt(3).
not correct
We have something like this : https://www.desmos.com/calculator/jpriys8xex
The equation of the ellipse is
(x - 4)^2 (y - 1)^2
______ + _______ = 1
16 1
The focal length ,c, is given by √ [ 16 - 1 ] = √(15) = c
So.....the distance between the foci = 2c = 2 √15 units
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+100 
