AUnVerifiedTaxPayer

Sorry, the answer choices got mixed up as well, here's the original problem.

If 3x−y=12, what is the value of 8x/2y?

A) 2^12
B) 4^4
C) 8^2
D) The value cannot be determined from the information given.

here's my solution. 

One way is to write

8x/2y

so that the numerator and denominator are writen with the same base. Since 2 and 8 are powers of 2, pluging in 2^3 for 8 in the numerator of 8x/2y gives

(2^3)x/2y

which can be written

2^3*x/2y (confusing)

Since the numerator and denominator of have a common base, this expression can be written as 2(3x−y). In the problem, it says that 3x−y=12, so can substitute 12 for the exponent, 3x−y, which means that

8x/2y=2^12

Heres a solution that I found. 

Multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x^2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x^2+25x−47=−8ax^2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x^2+25x−47=−8ax^2−3ax+16x−47

Since the coefficients of the x^2 term have to be equal on both sides of the equation, −8a=24, or a=−3.

The final answer is B.

I'm sorry for the exponents and the fractions, I'm just new to latex and don't understand it.

Sorry, I had a typo. its A circular table is pushed into a corner of the room, where two walls meet at a right angle. A point P on the edge of the table (as shown below) has a distance of 8 from one wall, and a distance of 9 from the other wall. Find the radius of the table.