So how do I ask an off topic question, also here is a problem for anyone who comes to this unfortunate post.
DEBUG THIS
x=y
x^2=xy
x^2-xy=0
2x^2-2xy=x^2-xy
2(x^2-xy)=(x^2-xy)
\(\frac{2(x^2-xy)}{(x^2-xy)}=\frac{(x^2-xy)}{(x^2-xy)}\)
2=1
:D
What you did was take the long way around to
say that two times zero equals one times zero.
And then you divided by zero to obtain 1 = 2.
.
+38 
