+0  
 
+2
2
2
avatar+47 

So how do I ask an off topic question, also here is a problem for anyone who comes to this unfortunate post.

 

DEBUG THIS

 

x=y

 

x^2=xy

 

x^2-xy=0

 

2x^2-2xy=x^2-xy

 

2(x^2-xy)=(x^2-xy)

 

\(\frac{2(x^2-xy)}{(x^2-xy)}=\frac{(x^2-xy)}{(x^2-xy)}\)

 

2=1

 

:D

 Sep 1, 2024
 #1
avatar+1079 
+2

 

What you did was take the long way around to    

say that two times zero equals one times zero.    

And then you divided by zero to obtain 1 = 2.     

.   

 Sep 1, 2024
edited by Bosco  Sep 1, 2024

0 Online Users