auxiarc

Why would you take the 3rd root of the r-value? And wouldn't that be ³√32 ? According to the solutions given, wouldn't it be 6, not 3?? 

And for the angle, I got -45 degrees, which equals -π/4, so if I divided that by 3, then I get -π/12.

Is that right? 

The square root of 28 is 5.29150262213.

Therefore, the square root of 28 lies between 5 and 6.

I get everything up until the last part, in the parenthesis. What do you mean 14pi/3 has to be reduced into an angle smaller than 2pi? How would I do that? 

Thank you. I understand what I did wrong. 

Much appreciation for you omigosh. You have no idea how much that helps. I also tried graphing it on Desmos but I did it wrong and I see where it messed up. Thank you for helping me. Seriously. :)

Oh, omigosh! Thank you so much! I see where I went wrong. I tried it for myself and also got the same answer! I appreciate your time and your help:)

I got

(2+4i)  /  (-3+2i)   x   (-3+2i)  /  (-3+2i)

= (-6-4i-12i-8i²)  /  (9+6i-6i-4i²)

= (-6-16i-8i²)  /  (9-4i²)

= (-6-16i-8(-1))  /  (9-4(-1))

= (-6-16i+8)  /  (9+4)

= (2-16i)  /  (13)        OR       2 / 13   x   -16i / 13

Ohhh! Okay, my bad. I will try that. :)

Yeah ! If you look at my work, then I did that. I'm just not sure if it's right. That's the only problem. :)

Okay so I was on the right track! I appreciate your help. Thank you so much!