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Divide (2+4i)  /  (−3+2i)

Answer in standard form for complex numbers.

 

 

I attempted this problem, but I'm not sure if it's right. If someone could possibly tell me what I did wrong, then I'd appreciate that. Thank you! 

Here's my work:

 

(2+4i)  /  (-3+2i)   x   (-3+2i)  /  (-3+2i)

= (-6+4i-12+8i2)  /  (9-6i-6i+4i2

= (-6-8i+8i2)  /  (9-12i+4i2)

= (2i+8(-1))  /  (-3+3i+4(-1))

= (2i-8)  /  (-3+3i-4)

= (8-2i)  /  (-7+3i). 

 May 13, 2020
 #1
avatar
0

2/13-16/13i

that should be the final answer

hope this helped

 May 13, 2020
 #3
avatar+1498 
+1

Guest, when answering questions, it's good practice to include work so the asker won't be like "what the wha"

 

:)

hugomimihu  May 13, 2020
 #2
avatar+1498 
+1

Wellllll

 

Keep in mind that a+b * a-b = a^2 -b^2

 

So you should actually multiply by

 

(2+4i)  /  (-3+2i)   x   (-3-2i)  /  (-3-2i)

 

And try this out!

 

I haven't done complex numbrs for a few weeks so I'm kinda rusty.

 

I'm pretty sure this should work.

 

I haven't tried it out but I'm reasonably sure that it should work

 

Update me on any progress!

 

If you don't understand anything feel free to ask.

 May 13, 2020
 #4
avatar+152 
0

Yeah ! If you look at my work, then I did that. I'm just not sure if it's right. That's the only problem. :)

auxiarc  May 13, 2020
 #5
avatar+1498 
+1

Haha

 

No, I meant -3 MINUS 2i, not plus.

 You wrote  (-3+2i)  /  (-3+2i) this

hugomimihu  May 13, 2020
 #6
avatar+152 
0

Ohhh! Okay, my bad. I will try that. :)

auxiarc  May 13, 2020
 #7
avatar+1498 
+1

I believe it should remove the complex number from the denominator and make it un-complex

hugomimihu  May 13, 2020
 #10
avatar+152 
0

I got

(2+4i)  /  (-3+2i)   x   (-3+2i)  /  (-3+2i)

= (-6-4i-12i-8i2)  /  (9+6i-6i-4i2)

= (-6-16i-8i2)  /  (9-4i2)

= (-6-16i-8(-1))  /  (9-4(-1))

= (-6-16i+8)  /  (9+4)

= (2-16i)  /  (13)        OR       2 / 13   x   -16i / 13

auxiarc  May 13, 2020
 #11
avatar+1498 
+1

Great job!

hugomimihu  May 13, 2020
 #8
avatar+111321 
+3

(2 + 4i)  / (-3 + 2i)      multiply num/den  by  the conjugate of -3 + 2i  =  -3 - 2i

 

So we have

 

(2 + 4i) ( -3 - 2i)

_____________   =

(-3 + 2i) (-3 - 2i)

 

 

-6 - 12i - 4i - 8i^2

_______________  = 

9 + 6i - 6i - 4i^2

 

-6 - 16i + 8

________   =

9 - 4(-1)

 

  2 - 16i

_________  =

  9 +  4

 

(2/13) - (16/13) i

 

 

cool cool cool

 May 13, 2020
 #9
avatar+1498 
+2

Oh Melody's not going to be happy with you

 

"I'd prefer if you gave hints and not full answers"

 

LOL

hugomimihu  May 13, 2020
 #12
avatar+152 
+1

Oh, omigosh! Thank you so much! I see where I went wrong. I tried it for myself and also got the same answer! I appreciate your time and your help:)

auxiarc  May 13, 2020
 #13
avatar+111321 
+2

HAHAHA!!!!!....it wouldn't be the first time that Melody was unhappy with me   !!!

 

And THX, auxiarc   !!!!

 

 

cool cool  cool

CPhill  May 13, 2020

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